6
\$\begingroup\$

I learned about this in primary school; but that is some years ago so I do not recall exactly how it was. I understand there is no correct way to do this – but anyhow we learned the "correct way". :)

I remember something in the direction of:

Having a picture of X × Y the mat should be some formula high, and some formula wide (if creating frame as well as mat). We also learned, as I recall, that the mat opening should be a tiny bit above, or below, centre; one border should be slightly thicker. This to drag the eyes downward, or to weight the picture down.

What is the standard way to measure this? I understand there is no correct way to do this — but as we learned some concrete numbers to work with — and they gave good results and would think there is some basic guidelines for this.

My most important question is which border should be thicker – and by how much.

I got really confused finding this post on eHow (see step 5), where they state the width should be greater. I definitely remember it was either top or bottom.

\$\endgroup\$
1

2 Answers 2

4
\$\begingroup\$

As I have learned it, the bottom border should be thicker than the other borders.

As with almost any rule of design or layout, this is not a strict rule to follow, just a guideline for what's balanced. If you want a different effect than a neutral, balanced frame, you can cut the mat any way you like.

\$\endgroup\$
1
  • \$\begingroup\$ Thank you for your reply; I came to the same conclusion as you have learned by testing some layouts. I also added a guide for one method that I guess is pretty "standard/classic". \$\endgroup\$
    – Luca Stein
    Commented Nov 30, 2012 at 17:39
3
\$\begingroup\$

Looking around, this is one of the more frequent methods I've found; same applies for both portrait and landscape: (Made a little guide as it is easier to read (picture from tumblr.com))

traditional mat guide

Giving us a result like this:

mat result

By calculating one could do – my geometry is a bit rusty so there is perhaps an easier way; but by taking advantage of angle by tan of opposite and adjacent side to the right triangle we get something like:

Having

a: mat width
b: mat height
c: image width
d: image height

We get

S: sides
T: top
B: bottom

By

S = (a - c) / 2

    a(b - d) + c(b - d)
T = -------------------
           4a

B = b - d - T

Alternatively B by:

     (3a - c)(b - d)
B = ------------------
            4a

Example

a = 21, b = 30, c = 17, d = 24

S = (21 - 17) / 2 = 2


b - d = 30 - 24 = 6

T = (21 * 6 + 17 * 6) / (4 * 21) = 2.71

B = 30 - 24 - 2.71 = 3.29
\$\endgroup\$
2
  • 1
    \$\begingroup\$ This photo is small enough that it's probably fair use, but it'd be better to choose something that's either yours or already licensed CC-BY-SA (the Creative Commons license used on this site). \$\endgroup\$
    – mattdm
    Commented Nov 30, 2012 at 18:15
  • \$\begingroup\$ @mattdm; OK. Thank you for that notice. I'll remember that. \$\endgroup\$
    – Luca Stein
    Commented Nov 30, 2012 at 19:25

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.