When would the appropriate time or scenario be to use different metering systems - spot metering, reflective or incident? And why? I do not understand when to use these.

  • \$\begingroup\$ There is no spot-reading incident meter, per se. That may help with some of the confusion. There are varying kinds of "directional" incident meter attachments for isolating specific sources, however. \$\endgroup\$
    – Stan
    Jan 20, 2018 at 20:13

1 Answer 1


Let's start with some definitions:

Reflective Metering

This is where you meter the light being reflected by the subject. This reading can be taken by a dedicated light meter or by the one built into your camera.

Spot Metering

This is a type of reflective metering where you meter the amount of light being reflected by a narrowly measured range. This range, when measured through your camera, changes based on the lens. Spotmetering.com reports a Canon 5d as using a 7.11 degree angle of measure when using a 50mm lens.

In this case, your camera would be measuring whatever is being reflected within a 7.11 degree angle, from wherever you're standing to the object reflecting light.

A dedicated light meter, on the other hand, can have an angle of measure as small as 1 degree.

Incident Metering

This is where you use a dedicated light meter to measure the amount of light falling on a subject (as opposed to being reflected by a subject)

When would the appropriate time or scenario be to use different metering systems?

The "truest" or most accurate measurement will be made with an incident light meter. Reflected metering tends to measure everything assuming you want middle gray. While this works in many situations, it tends to error when photographing either very bright things (causing them to underexpose) or very dark things (causing overexposure). You can test this by metering a white shirt. Shoot a "proper" exposure. Now manually force the meter to read +2 and shoot again. The "overexposed" shot will be a better exposure.

You could also compare the meter reading from an incident meter placed next to your shirt and compare it to what your camera says.

Given this, why would anyone ever not use incident metering? The answer is fairly simple: you can't get to your subject. Maybe your subject is a grizzly bear, maybe it's a soccer player. In either case you will need to use a reflected meter.

Your camera probably has Evaluative, Center Weighted, and Spot metering modes.

So why use spot?

You want to use spot metering when the scene is highly contrasted or backlit - in situations where the exposure is going to vary wildly across the scene and so you want to make sure that your actual subject is exposed properly.

Why use the spot meter on a dedicated light meter vs. what's in your camera?

Honestly, I wouldn't. The exposure difference will be more accurate with the dedicated light meter - but it will probably be very close to what the camera says. In these situations, I find it easier to take a shot and check the histogram as opposed to getting the light meter out of the bag,

  • \$\begingroup\$ Many camera models also have spot metering that can be as narrow as 1 to 2 degrees. The Canon EOS 1D X Mark II and 5D Mark III both have 1.5° spot metering. The EOS 5DS, 5Ds R, and 5D Mark IV have 1.3° spot metering. The EOS 7D Mark II has 1.7° spot metering. \$\endgroup\$
    – Michael C
    Jan 20, 2018 at 1:28
  • \$\begingroup\$ @MichaelClark, you sir, are a walking encyclopedia. Props. Are those degree ratings consistent across all lenses or will they vary a bit? \$\endgroup\$
    – OnBreak.
    Jan 20, 2018 at 15:57
  • \$\begingroup\$ That's what Canon publically releases with their camera specs. I'm not sure why lens would matter for the built in meter, since it is measured as a percentage of the surface area of the viewscreen in the camera. You only need to worry about FoV (based on FL + format size) when using an external meter. \$\endgroup\$
    – Michael C
    Jan 20, 2018 at 16:42
  • \$\begingroup\$ Never mind. I'm reading all of the degrees in your answer as "percent". Substitute "percent" for "degrees" in my comment above. \$\endgroup\$
    – Michael C
    Jan 20, 2018 at 16:47
  • 1
    \$\begingroup\$ With a FF sensor, a 1.5% spot meter would have a radius of 0.04698X the diagonal FoV of the lens. For a 50mm lens with a 46° diagonal FoV, that would equate to 2.16°. So the diameter of the spot meter would cover a 4.32° AoV. \$\endgroup\$
    – Michael C
    Jan 20, 2018 at 17:00

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.