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I am a beginner in this topic, so I dont know if it is possible what I try to do.

First of all, I have the following HF35HA-1B lens: enter image description here

It says the maximum sensor size is 2/3", but I have a non-standard 25mmx25mm image sensor, so I want to do some hackings. I know the flange focal distance of Cmount lenses is 17.526mm, but what if I move the image sensor further back from the lens? I suppose the further I go from the lens, the bigger image I get. But how can I calculate the radius of the image circle? I did a very easy test, in which I could make sure that even if I move the sensor back the image is focused for closer objects, so I think that is not an issue. But I would like to calculate the image circle to make sure the image sensor is in the image circle. Is it even possible what I am trying?:)

I would appreciate any comments!

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If your lens's "max sensor" size is 8.8mm × 6.6mm, then the image circle projected onto the sensor is just the sensor's diagonal measurement, 11mm (from Pythagoras: √(8.8² + 6.6²)).

The diagonal of your 25mm × 25mm sensor is 35.4mm diagonal, which is 3.21 times larger than the lens's spec image circle.

Thus, you need "extend" the focal length of the lens 3.21 times. Or put another way, in addition to the lens's built-in focal length, you need to add 2.21 times the actual focal length. 2.21 × 35mm = 77.5mm of extension.

This will cast an image circle with the same degree of vignetting onto your 25mm × 25mm sensor as it does on a 8.8mm × 6.6mm sensor (where "degree of vignetting" is number of stops of light loss as a function of percentage of distance from center of lens to corner of sensor).


This much extension will have substantial effects on your ability to focus. When you add distance between the lens and the camera body (with extension tubes, bellows, etc.), there are two main effects:

  1. you can focus closer than you could without the extenion (your Minimum Focus Distance decreases); and
  2. you can no longer focus far away, such as infinity (you Maximum Focus Distance decreases).

How much does the Maximum Focus Distance decrease?

Let's first focus the lens with focal length ƒ at infinity, which is the "native" maximum focus distance. Then, without changing the focus ring on the lens, let's mount an extension tube with length X between the lens and camera body.

The new maximum focus distance D' is given by the formula

D' = ƒ * (1 + ƒ/X)

In your particular case, X = ƒ × 2.21, so the equation becomes D' = ƒ * (1 + 1/2.21) = 1.45ƒ = 51mm. (!)

That means that for the lens you're trying to use, if you want it to project an image circle onto a sensor that's 3.21 times larger than it was designed for, if you add the correct extension, you can only focus up to 51mm in front of the lens.


What you want to do is possible, but it's probably not practical for any real-world interesting usage.

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I don't quite understand what the spec means by "max sensor size," but I suspect they mean that this lens will have significant vignetting outside that radius at the standard back-focal length. Now, to estimate the image circle, you need to decide what the maximum object size, or to be precise, entrance angle, is going to be. Then a simple primary-ray raytrace will show you the image circle at the focal plane. Remember that there's only one back-focal distance for a given object distance (the lens focusses by moving internal glass to change the effective back-focus distance.) Use this diagram as a guide (source: wikimedia) primary ray path

If the Object is extremely tall, then the RealImage (essentially the image circle radius) will get large as well. But in practice, the lens will have terrible distortion, and shift in focal length, as well as vignetting, beyond its rated image circle size.

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C-mount is a technical specification that provides, among other things, a standard distance between the camera sensor plane and the point where the camera lens meets the camera body. At this distance the lens you are looking at will produce an image circle of a specific size (large enough to cover a 2/3" sensor with acceptable sharpness (for some definition of 'acceptable')). If the distance between the mount point of the lens and the sensor plane is different the size of the image circle will be different (larger if greater, smaller if less).

A 2/3" sensor is 8.8mm x 6.6mm, substantially smaller than the 25mm x 25mm sensor at hand. To cast an image circle over the sensor with the lens of interest, the distance between the rear of the lens and the sensor plane must be increased. Because the amount of light passing through the lens is independent of the distance between the rear of the lens and the sensor plane, increasing the distance will result in less light per unit area hitting the sensor (average luminance).

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    You got off of the correct columns. Fuji 2/3" sensor is 8.8x6.6 mm. The diagonal is 11.0 mm. The number 2/3" has essentially zero meaning. – WayneF Jan 20 '17 at 17:55
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Searching the web for data on this lens, I have found published angles of view for other imaging sensors. Thus I surmise that the circle of good definition for this lens has a diameter about equal to its focal length. Such an illuminated diameter is the rule of thumb for most lenses.

You can hand-hold this lens, projecting an image, perhaps a view through a window, onto a white screen, which can be ordinary white paper. This will allow you to inspect to see if the lens barrel has internal baffles that reduce the diameter of the projected image. I suspect this is not the case.

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