# What does f-stop mean?

What does f-stop mean? Is it the same thing when people say "2 stops" for example?

• See also What is one "stop"? Commented Oct 25, 2014 at 11:31
• Commented Oct 25, 2014 at 11:34

An f-stop is kind of a combination of two terms. First off, f/N is generally the notation used to indicate the size of the diaphragm opening, or aperture, in a camera. Let me give a little detail about how that notation came about, before I go on to explain the meaning of a stop.

## Aperture Values and f/Stops

Aperture openings are measured as fractions of the focal length of a lens. That is what the 'f' stands for in the aperture rating, 'focal length'. Assuming we have the epitome of lenses, the 50mm, with an aperture of f/2.8, we can determine the actual diameter of the aperture opening like so:

50mm / 2.8 = 17.85mm

If we open the aperture up to its maximum of, say, 1.4, we can measure that as well:

50mm / 1.4 = 35.71mm

The difference between an aperture of f/2.8 and an aperture of f/1.4 is a difference of four times as much light...or two stops. We know this because the area of the aperture opening itself is four times as large at f/1.4 (1001.54 mm2) as it is at f/2.8 (250.25 mm2). A stop in photography nomenclature means a difference of one exposure value, which is the doubling, or halving, of the amount of light reaching the sensor. There are a few standard "full stops" that f-numbers are rated in:

1, 1.4, 2, 2.8, 4, 5.6, 8, 11, 16, 22, 32, 45, 64

These aperture settings all differ by one full exposure value, or one full "stop", and create the full f-stop scale. When you close down your 50mm f/1.4 lens from its maximum aperture of f/1.4 to an aperture of f/2.8, you are "stopping down" by two full stops.

It should be noted that most cameras these days offer a two additional f-stop scales beyond the standard full stop scale: a half-stop scale and a third-stop scale. Most cameras default to a fractional scale rather than the full stop scale, so it is important to learn and memorize the full stop scale so that you are making the proper adjustments when you change your aperture setting on your camera.

Half-stop Aperture Value Scale

1, 1.2, 1.4, 1.7, 2, 2.4, 2.8, 3.3, 4, 4.8, 5.6, 6.7, 8, 9.5, 11, 13, 16, 19, 22

Third-stop Aperture Value Scale

1, 1.1, 1.2, 1.4, 1.6, 1.8, 2, 2.2, 2.5, 2.8, 3.2, 3.5, 4, 4.5, 5.0, 5.6, 6.3, 7.1, 8, 9, 10, 11, 13, 14, 16, 18, 20, 22

## Relationship with Shutter Speed

An important relationship exists between aperture and shutter speed. Both are rated in stops. While aperture differences are often denoted in 'f/stops', shutter speed changes are usually simply called 'stops', or possibly exposure values.

Back to our example with the 50mm lens. Assuming we are shooting on a bright sunny day, with an ISO of 100. We have the aperture set to f/16, and the shutter speed set to 1/100th. (This is called the "Sunny 16" setting, as photographic theory indicates that an f/16 aperture, with a shutter speed matching the ISO speed, will produce a proper exposure in bright midday sunlight.)

Assuming we need to shoot something that is moving very fast, and we need a higher shutter speed. We can easily calculate the proper aperture value, assuming we know how many stops of additional shutter speed we need. If we increase our shutter speed to 1/200th, that is a difference of one whole stop. Shutter speed and aperture are inverses of each other, so if we increase shutter speed by one stop, we must open the aperture by one f/stop, to f/11. Despite the difference from the original settings, the new settings will produce the same exposure. The same applies if you are using a half- or third-stop scale...any half or third stop adjustment of one setting requires an similar inverse adjustment of the other.

• One mistake in the last paragraph: f/16 to f/8 is two stops, not one. Commented Sep 3, 2013 at 19:13
• f/x.y is troubling me. For the number and decimal, I'd rather go with n.n or N.n or even f/#.# rather than the traditional letters that are used to designate abscissa/ordinate directions or unknowns.
– Stan
Commented Sep 5, 2013 at 0:14
• If anyone is wondering why the range of numbers has 1.4 and it's multiples: 1.4 is about the square root of 2. To double the area of a circle like the light stopper within your lense (which you set with the aperture), you must double the radius squared (r² in π*r²). To double r², you must increase r by the root of 2. 2r² = (squareroot(2) * r) ². Hope that helps! Commented Apr 19, 2020 at 18:28
• I wonder about the word "stop": Could it be, because for the old lenses you could feel the next value without having to look at it, so turning the ring until you feel the next "stop"? Commented Apr 28, 2023 at 20:53

An f-stop is a mechanism for setting the aperture of the lens, or how wide it is opening to let in the light.

There's two parts to it: f and stop. First, the maths.

• f-number

An f-number is a number in the form f/2.0 which specifies the size of the aperture opening.

f refers to the focal length.

f/2.0 means the diameter of the aperture opening is the focal length divided by 2.0.

f/4.0 means the diameter of the aperture opening is the focal length divided by 4.0.

That's why if the number on the right is bigger, the aperture is smaller.

These both measure effective aperture: that is, in a hypothetical single-element lens, what is the diameter of an equivalent aperture placed right on that lens. In a lens with multiple elements, for engineering reasons, the actual aperture opening may differ in order to match up with this.

• stop

It's originally called a "stop" because an old-style aperture ring "stops" at certain settings - that is, it has markings where the ring stops.

These "stops" are specifically designed such that each "stop" lets either half or double the amount of light in as the stops before and after it.

The common aperture stops are f/1.4, f/2.0, f/2.8, f/4.0, f/5.6, f/8.0 and so on. The space between two consecutive numbers in this sequence is what is also called a "stop".

(Note that some aperture rings had half-stop markings in between these too.)

But wait a minute! You may be wondering why each one of these is the previous one divided by √2 not 2. Why? Because halving the area of the aperture requires dividing the diameter by √2. This is because the area of a circle scales with the square of its radius.

So even though each number is not double or half its neighbours, it still lets in double or half the light of its neighbours.

Thus, this is why the stops go up in those numbers. Of course, 1.4 isn't exactly √2. The numbers are simply rounded to only one digit.

Modern digital cameras don't usually have an aperture ring anymore, and let you set the aperture to any value, or to increment or decrement it by half-stops or third-stops. This is the equivalent to setting an old-style aperture ring to rest in between two whole-stop markers (some rings had detents in half-stops to help this).

Now that you know how f-stops relate to aperture and the amount of light reaching the sensor, you can use the term "stops" as a general term to refer to a doubling or halving of light for any reason.

For example, you may refer to quadrupling the ISO setting as "increasing the ISO by 2 stops".

The "f-stop" is the figure for measuring the aperture, and is measured as a ratio of the focal length (that's the "f").

So, at 100mm focal length, with an f-stop of f/2.8, the aperture is physically about 35mm wide.

Nowadays, most cameras allow the aperture to be adjusted by a third of a stop or half a stop, but "a stop" is either halving the size of the aperture (so f/2.8 to f/4) or doubling it (so f/5.6 to f/4).

Similarly, with shutter speeds, one stop is either halving the time ( 1/60 -> 1/120) or doubling it (1/60 -> 1/30)

• Your answer is mostly correct. Minor adjustments needed though; the next smaller full f-stop after f/2.8 is f/4, not f/5.6 (it comes after f/4). f/4 has an area that is half of that for f/2.8. This means that 1/60 sec at f/2.8 will give the same exposure as 1/30 sec at f/4. Commented Jul 16, 2010 at 15:37
• Another correction: The f-stop does not measure the physical size of the aperture, it measures how large it looks when viewed from the front lens, i.e. how much light it actually lets in. Commented Jul 16, 2010 at 16:20
• @Guffa: are you really sure? Can you provide a reference (it's the first time I hear about it)? I have always read that it was simply the focal length divided by the aperture diameter. Commented Jul 16, 2010 at 16:37
• @Frefrik: Yes, it is the focal length divided by the aperture diameter, but it's not the actual aperture diameter, but the effective aperture diameter. chestofbooks.com/arts/photography/… If it was the actual aperture diameter, different lenses would give completely different exposure for the same f-stop setting. Commented Jul 16, 2010 at 18:11

Why not use millimeters to measure the aperture size? Why do we even bother with this system?

Because physics: http://imagine.gsfc.nasa.gov/YBA/M31-velocity/1overR2-more.html

Let's say we used millimeters to measure the aperture instead. You compose your shot, meter your scene and choose your settings. If you decide to zoom in, changing the focal length (and the opening stays the same fixed size)...the quantity of light hitting your sensor will change, so now you have to change settings again. If we use f-stops, we can zoom in (change the focal length) without changing the quantity of light hitting the sensor.

The link above basically says that each time you walk your sensor one step farther away from the light, the quantity of light hitting the sensor decreases by a greater amount each time (instead of decreasing by the same amount for each step). In other words, light intensity at a given location (the location of the camera's sensor) follows an inverse square law (it is equal to one divided by [the distance between that location and the light squared]).