The specs on the Nexusw 5 rear camera are: Aperture size: F2.4 Focal length (35mm equivalent): 30.4 mm Camera sensor size: 1/3.2"
I want to calculate the field of view for this camera. Using FOV=2*atan(W/2/f) where: FOV=field of view W=camera sensor size f=focal length From a table of image sensor formats 1/3.2" sensor has a horizontal size of 4.54mm. This gives a FOV=2*atan(4.54/2/30.4)=8.54 degrees.
So if the subject is 1m away from the lens, the calculated field of view at the subject is D*tan(FOV/2)*2=1*0.0747*2=0.149m.
If I position a nexus 5 camera 1m away from a subject I can see much more than 0.149m of the subject.
Why is my calculation wrong?