I am trying to figure out how big an object of, say, 50cm height at 100m distance and 600 mm focal length would appear on a camera's sensor. The ubiquitous formula
$$ \textrm{object size in image} = \frac{\textrm{focal length} \times \textrm{object size}}{\textrm{object distance}} $$
yields
$$ \textrm{object size in image} = \frac{\textrm{600 mm} \times \textrm{.5 m}}{\textrm{100 m}} = \textrm{3 mm} $$
What I am wondering: Are these 3mm entirely independent of sensor size?
E.g., a specific superzoom model has a 1/2.3" sensor (= 4.55mm height according to one source) and a maximum zoom quoted to have a "35mm equivalent focal length of 600mm". Would the object actually cover 3/4.55 = approx. 66% of this sensor's height = 66% of the image, or does the relation between the sensor size and the "35mm equivalent" have to be taken into account somehow?
(My apologies if this has been asked before - I have found many related questions, but not this one.)