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When my Pentax K-r applies long exposure noise reduction (dark-frame subtraction), the processing time required for this operation is less than the exposure time. For example, my camera may perform noise reduction for 10 seconds after a 15 second exposure. Why?

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  • \$\begingroup\$ On some cameras there is a cap. So that it does not take too long, I guess. IIRC, on the K10D and K20D it was 30s. I have not received a K-r yet so I cannot confirm that it is normal. The user manual is rarely helpful with such details. \$\endgroup\$
    – Itai
    Jun 25, 2011 at 3:01
  • \$\begingroup\$ There is no cap on my K-r. I've had exposures several minutes long and the dark-frame subtraction time continued to increase with the exposure time, but it was never as long as the actual exposure. \$\endgroup\$
    – bwDraco
    Jun 25, 2011 at 3:13

3 Answers 3

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The manual gives you your answer:

Determines conditions such as shutter speed, sensitivity, and internal temperature, and automatically applies Noise Reduction as necessary. (default setting)

This implies that the algorithm for noise reduction isn't a simple 1:1 match with the exposure time and, coupled with the quality of the K-r/K-5 sensor family, the amount it would normally have to apply would have been less than with the prior cameras.

For myself, I have it turned off for my K-5s. I would rather deal with the noise after the fact and not have the camera lose time repeatedly doing this action.

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  • \$\begingroup\$ I never drew this conclusion from what the manual said... Thanks! \$\endgroup\$
    – bwDraco
    Jun 25, 2011 at 13:32
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There are a couple of possibilities here:

  • The camera has a saved dark-frame it is using as a reference.
    • (Unlikely, since the time is not constant. However, saved dark-frame subtraction does work pretty well - it's often used in astrophotography, where exposure lengths are so long taking an equivalent dark frame for every exposure is not a viable option.)
  • The dark-frame is being done at a higher ISO

Basically, a CCD/CMOS is a bunch of electron wells. As they are are struck by photons, the photons knock electrons loose, and the electrons fill the wells. The more light, the more electrons in a well, until it fills up and you get blown highlights.
However a Image sensor is not a perfect system, and electrons leak into the wells over time. This is what the "Dark Frame" is measuring - the rate at which the wells fill in the absence of light.

Fortunately, the rate at which each well leaks is fairly constant (particularly over short time scales). Therefore, a dark frame exposure of 4 seconds will probably look very much like a dark frame exposure of 2 seconds, multiplied by 2.

Therefore, it is possible that the camera is simply taking a shorter dark-frame, and using a higher ISO (which effectively is just a way of multiplying the number of electrons in each well) to generate a equivalent dark frame in a shorter period of time.

It is very unlikely to be related to sensor temperature.

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Theoretically the "dark frame" exposure time should be the same as the "light frame" to accumulate the same amount of noise. This is only true if the temperature of the sensor is the same.

Basically there are two options:

  • Ensure that the sensor temperature is the same. (cooling the sensor).
  • Use different temperatures and compensate it with different exposure time.

My guess is the following: K-r measures the temperature of the sensor and specifies the length of the dark frame based on this. Since the temperature is usually higher after a long exposure the dark frame can be shorter.

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  • \$\begingroup\$ I don't see why this should be downvoted. Temperature is indeed measured by the camera and used to determine noise reduction. \$\endgroup\$
    – bwDraco
    Jun 25, 2011 at 13:33

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