I am trying to fully understand EV (exposure values) as used in photography. This is a system intended to simplify camera shutter speed/aperture combinations using a single value instead of two.
EV calculation using log base 2 EV=log ((N²/t) where N = camera’s f-number setting and t = shutter time in seconds. This is the classic method.
Alterative using base 10 EV= 3.32 log N2/t
Both equations yield approximately the same answer. What I am asking is the significance of the value 3.32. Is this a conversion factor log base 2 to log base 10?