How do I convert from the percent magnification that many photo editing apps use to times magnification? For example, if I have taken a photo at 30mm and then zoom to 100% percent in Lightroom, what focal length would that correspond to?

  • 3
    what are you actually trying to do? or to understand? The focal length is a physical property of the lens. The 100% view of a digital image is where one pixel in the image (images are made of pixels, right?) takes up one pixel of your display. I don't think you should be trying to equate these concepts. Again, what are you trying to achieve or understand by that?
    – osullic
    Jan 19, 2021 at 0:22
  • What is the resolution of the camera's sensor? Assuming you take two images with two different cameras with the same size sensor and using the same lens: If one camera has 20MP and the other camera has 80MP, viewing each at 100% will enlarge the the 80MP by twice the linear magnification factor (and 4X the areal magnification factor) than the 20MP image. That's one reason comparing images from different cameras with different pixel densities at 100% is not an equal comparison. They're being magnified by different amounts.
    – Michael C
    Jan 19, 2021 at 5:41
  • The magnification % you are revering to in editing software is not a tool to change what focal length was used when you shot the photo or change the focal length in the file. It simply makes the photo physically larger or smaller by the percentage you choose. The Cropping tool will give a perceived focal length change.
    – Alaska Man
    Jan 19, 2021 at 20:56

5 Answers 5


The percentage is the scaling applied to render the image onto the display. The size of the image on screen will therefore depend on your screen size. Conceptually this can be thought of:

  • 100% means that each pixel of the image is shown as 100% of a pixel on screen.
  • 200% is zoom in because each pixel of the image takes 200% of a screen pixel which is 2 pixels vertically and 2 pixels horizontally, so 4 pixels in total.
  • 50% zooms out because each pixel is represented by a 1/2 screen pixel, so 4 image pixels get mapped to a single screen pixel since image pixels are scaled 50% horizontally and vertically.

For those who take issue with the simplification of the above list, strictly speaking the mapping can be more complicated to provide a clearer zoom but in terms of scale, that is what happens.

The percentage zoom is unrelated to focal-length. It is simply a pixel-to-screen scaling.

  • There's no such thing as taking 50% of a screen pixel. One pixel is the smallest RGB unit on a screen. At 50%, each screen pixel would be combining a 2x2 (width x height) group of image pixels. Also, 200% zoom would take 4 screen pixels per image pixel. Two in width by two in height.
    – Michael C
    Jan 19, 2021 at 5:55
  • Of course, this was to illustrate the mapping conceptually. Clarified the text to point that out.
    – Itai
    Jan 19, 2021 at 15:21
  • 1
    The visible/remaining FOV does directly correlate to (effective) focal-length. It doesn't matter if it's due to sensor size, cropping in post, or display zoom level. And that is the question that was asked... Jan 19, 2021 at 16:48
  • @StevenKersting But it will differ for various screens with differing resolution. Magnifying a 24MP image to 100% on an FHD (1920x1080=2MP) monitor will crop more of the image than magnifying the same 24MP image on a 4K (3840x2160=8MP) monitor by a linear factor of 2X. So there's no direct correlation, it's a variable one based on sensor pixel density as well as monitor resolution and pixel density.
    – Michael C
    Jan 20, 2021 at 5:38
  • @MichaelC, what does that matter? The (paraphrased) question is "How does it correlate to FL if I change the zoom level when viewing on my monitor?" (or any given monitor for that matter). That could be useful if someone was trying to decide what FL might suit them better for a specific subject/situation. And the answer that "starts with the zoom level that causes the image to fill the screen" suits the question IMO. Jan 20, 2021 at 14:50

There's no direct constant relationship between the two things.¹

This is because different cameras have different pixel densities as well as different sensor sizes.

It's also because different display devices also have different sizes and pixel densities.

You can view the same image at 100% on two different monitors and the total magnification factor will be different if the monitors have different pixel densities.

Or you can view images from two different cameras on the same monitor at 100% and have different magnification factors because the two cameras have different pixel densities.

When you view an image at 100% on a display device, it means you are using one pixel group (one RGB set) on the monitor to view one pixel in the image at a 1:1 correspondence. 100% is not an expression of a specific amount of magnification, it's an expression of the ratio between the number of pixels, in linear terms, on the screen and the number of image pixels being displayed, in linear terms, on the screen.

If you have a 1920 x 1080 monitor and an image that is 1920 x 1080 pixels, then viewing the image full screen would give a 100% view. But if you take a 3840 x 2160 pixel image and view it at 100% on the same monitor, you'll only see 1/4 of the entire image: half of the width and half of the height. That's because the second image is twice as many pixels wide and twice as many pixels high, which gives four times as many pixels in the image compared to the number of pixels the screen has.

¹ That is, between focal length and screen magnification.


There are some "broken links", some "unrelated" steps and variables in the process to know a magnification of an image on your screen. Let me summarize.

enter image description here

A) Size of the object

B) Shape of the object

C) Distance to the object

D) Focal length

E) Internal optics of the lens

F) Sensor size

G) Megapixels of the sensor

G1) Actual configuration on the camera of the Mpx used

H) Resolution on your screen

I) Configuration of the resolution of the graphics card

J) Or if you have a projector the resolution of the projector

K) The optics of the projector

L) Distance for the projection

M) The final size

And the only variable we actually know is that the software is displaying 100% zoom, this is 1 image-pixel to 1 screen-pixel

If we know all the variables we might have the real ratio of magnification.

One example of how "magnification" means on some section of this diagram is here: What does "magnification" mean?


100% = "actual pixels". A pixel on your monitor equals a pixel from your camera. OK, not exactly, if your computer display scaling is not 100%, then there is another complication, but that can be ignored for this calculation.

You need to start with the zoom level that causes the 30mm image to fill your monitor/editing window. Then multiply the focal length by the ratio of the percentages. E.g. if your image was taken with a 30mm lens, and 10% zoom fills your window; then at 100% zoom this will be the equivalent of 30mm * (100%/10%) = 300mm.

This is an approximation that works for normal lenses. For an ultrawide, it won't be nearly as accurate. There may be a lens geek here that knows how to convert for any lens focal length.

Edit: Test on my camera. All images taken from exactly the same spot. All images uncropped. Some are zoomed of course.

26mm shot, display percentage set to fill the screen enter image description here

Same shot (26mm) displayed at 100% enter image description here

73mm shot with display adjusted until the checkerboard was the same size as the previous (26mm) image. Had to set the percentage to 34% to get them to be the same size. enter image description here

Now calculate the ratio to predict what focal length should give the same field of view:

100%/34% * 26mm = 76.5mm. close to 73mm. Not perfect, but fairly good evidence that this method works.

  • "100% = "actual pixels". A pixel on your monitor equals a pixel from your camera" ... no ... IMAGE being edited, which may or may not relate to the original camera image. If 10% fills my little monitor and 100% fills my big monitor, nothing can be said about equivalent focal length because the concepts are unrelated. Jan 19, 2021 at 4:47
  • Alternatively, if 10% fills my old low resolution monitor and 20% fills my newer high resolution monitor of the same physical dimesions, the image is exactly the same size on both. Again nothing can be said about equivalent focal length because the concepts are unrelated. Jan 19, 2021 at 4:56
  • @user10216038 - well, of course I am assuming that this is an image straight from the camera, uncropped.
    – Mattman944
    Jan 19, 2021 at 9:31
  • Your image additions demonstrates that image cropping can produce a similar image from a longer lens, not accounting for resolution loss. How big it's displayed on a media is not relevant because pixels have no physical dimension. Jan 19, 2021 at 16:39
  • @user10216038, The question was in relation to an image taken on their camera and viewed on their monitor in order to correlate (effective) FL and FOV. I think this answer suits perfectly well. And there is no difference in this aspect between an actual crop and display crop due to being oversize. Jan 19, 2021 at 16:43

This percentage is a ratio of the displayed image to the full-size image.

If your viewing application is in "dot-for-dot" mode (one pixel in the source image is one pixel on the screen, which is usually the default) then at 100% you actually have a one-to-one mapping between pixels on screen and in the source image (de-mosaiced camera sensor "pixels"). At 50%, a pixel on screen is the interpolation of a 2x2 square from the source, and at 200% a 2x2 square on the display represents one pixel of the source.

In non "dot-for-dot" viewing modes, the viewing application checks the "print definition" in the image, which indicates how big the image should be in print (print size = pixels ÷ print definition) so the zoom ratio is the ratio of the image on the screen to the image in print (this assumes that the application knows the pixel density of your screen but it can find this out). However, since by default the print definition is 72PPI (and this is not specified in pictures from cameras) the default print size of your image is about twice bigger than that of the dot-for-dot view (because modern "standard" displays are around 120-150PPI) so the 100% in dot-for-dot produces roughly the same size as 50% in "print size" in mode.

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