I know my question is a bit general but I am super confused as the range of available lenses is amazingly wide. I am looking for an ultrawide lens for my gears (D810 and D3300) to do: 1. Landscape Photography 2. Star trail night Photography

I looked over DXOmark scores but they don't cover all available lenses. I currently have a NIKKOR 24–120mm f/4G ED VR so I guess a 12-24mm lens would be perfect.

  • 3
    \$\begingroup\$ What specifically is your question? \$\endgroup\$ May 30, 2019 at 19:52

2 Answers 2


It is hard to find an ultrawide lens that will work well with both crop bodies and full frame cameras. This is due to the following:

  • To get the same angle of view with a 1.5X APS-C crop body one must have a lens with 1/1.5x the focal length of a lens needed for the same angle of view on a FF body.
  • For the same focal length, to get a larger image circle needed to cover the full sensor of a FF body, it is much more difficult (and expensive) to design a wide angle lens for a FF body than for an APS-C body.

In general, you'll get the best image quality by using a FF camera with a FF UWA lens like the AF-S Nikkor 12-24mm f/2.8G ED-IF. It will give the same angle of view with your D810 that an 8-16mm DX or FX lens would provide on your D3300. But if you use the 12-24mm DX lens on your D3300, you'll only get the same angle of view as you would with an 18-36mm FX lens on the FF camera.

The reason the FF 14-24mm lens is so much more expensive is two-fold:

  • At 14mm it has a wider f/2.8 aperture that requires an entrance pupil with twice the area of a 14mm f/4 lens. This requires lens elements with larger diameters.
  • It must project an image circle with a diameter of over 44mm, compared to an APS-C sensor that only requires a 29mm image circle. This requires bending light more strongly at the edges of the wider angle of view.

Keep in mind that if both lenses are 14mm, they will magnify by the same amount in terms of the image they project onto the camera's sensor. To get a larger image circle means the lens with the same focal length must collect light from a much wider angle of view. This requires the FF lens to bend light from the wider angles much more than an APS-C lens has to do for the narrower angle of view it provides to a crop sensor.

To put things another way:

  • If you use the 12-24 f/4 DX lens on your D3300 or on your D810 (which will automatically crop to only the center part of the D810 sensor that is the same size as the entire D3300 sensor), you'll get the same angle of view as an 18-36mm full frame FX lens would provide on the D810.
  • If you use the 14-24mm f/2.8 FX lens on the D3300, it will give the same angle of view as you'd get with a 21-36mm FX lens on the D810.
  • Only if you use the 14-24mm f/2.8 FX lens on the FF D810 will you get the widest angle of view. You'd need a 9.3-16mm lens to get the same angle of view with the D3300.

For astrophotography, you really want a lens with the widest aperture you can afford. You'll usually get much better results using a FF sensor with a 14mm f/2.8 lens than a crop sensor with a 12mm f/4 lens.

  • \$\begingroup\$ Thank you so much for the explanation - it was super useful! \$\endgroup\$
    – Perissiane
    May 31, 2019 at 0:02

The Nikon 12-24 mm f/4 lens is a good one, but is a DX lens for the D3300. The 14-24 mm f/2.8 lens is substantially more expensive, but will work (with full frame coverage) on either body (like the 24-120 mm f/4 works on either body). The D810 can use the 12-24 mm DX lens, but then that frame will be cropped to the DX view, about 42% area, or 4800x3200 pixels, which when so cropped is the equivalent view of an 18 mm full frame lens (counterproductive to wide angle).

  • \$\begingroup\$ So I guess my best bet is something like Samyang 14mm f/2.8 IF ED. Do you happen to know the difference between the Aspherical version of it and the most recent one which is UMC? \$\endgroup\$
    – Perissiane
    May 31, 2019 at 0:05
  • \$\begingroup\$ Sorry, no, I am not familiar with that one. \$\endgroup\$
    – WayneF
    May 31, 2019 at 3:17

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.