2
\$\begingroup\$

In analog printing color negative film to RA-4 paper, one approach is to project the image to the easel, place a diffuser in the light path, and then place a filter calculator (an array of filters of varying magenta+yellow filtrations) on top of the paper and make a test print. The filtration on the test print closest to gray is supposed to be the correctly color balanced one for the image. How and why does this work? If I take a picture of a red wall, for example, I wouldn't expect the image to average to gray. (Understood that this works MOST not ALL of the time.)

\$\endgroup\$

1 Answer 1

4
\$\begingroup\$

To achieve an equitable color balance, it is necessary to present the paper with a spot-on mix of red, green and blue exposing light energy sourced from the projected image of the negative. If the exposing light mix be biased as to color or intensity, substandard print results.

Now the vast majority of images contain substantial neutral areas, we are talking black, gray and white in varying densities. Should these neutral areas reproduce with a color tint, an observer will declare, the image is off-color. This description being true most images integrate to gray. Integrate means we can laminate a print to a top and spin this affair at high-speed we will be viewing a blurred - gray image. We can also view this grayed integration if we optically scramble this image using diffusion.

Note: If the image is comprised of large areas of strong color, it will not integrate to gray and the method you describe will not yield a satisfactory filter pack. Let me add, the method you describe yields a good start filter pack for the majority of typical negatives. I say good start because every print made will require touch-up filter pack adjustments and exposure adjustments that fine tune resulting print. Also, the principle behind using a gray card target to measure exposure is based on the fact that a typical vista integrates to a battleship gray with about 18% reflectivity.

\$\endgroup\$
4
  • \$\begingroup\$ Couldn't you also scan the image (or take a digital image) and diffuse or "average" it digitally -- i.e in Photoshop? \$\endgroup\$
    – bvy
    Feb 22, 2019 at 15:04
  • \$\begingroup\$ @ bvy -- High-speed photofinishing printers initially used photo multipler vacuum tubes to read integrated red, green and blue densities of each negative. These were replaced by solid state photodiodes. These systems evolved into primitive scanners and then modern scanners. Specialized software sets the exposure time and the degree of optical filtration on a custom basis for each negative. \$\endgroup\$ Feb 22, 2019 at 16:16
  • \$\begingroup\$ That's certainly interesting, but it doesn't answer my question. Is it possible to reproduce this physical diffusion or "averaging" with a digital image and process, and show that "most images" go to gray? \$\endgroup\$
    – bvy
    Feb 22, 2019 at 18:44
  • \$\begingroup\$ @ bvy -- All I can tell you is : We can use the data from the scan to control the exposure i.e. how much red, green and blue energy is needed to expose color paper and obtain an optimum print. This can be so precise it can even take into account film emulsion batch differences of the same brand and type of film. The software is specific for this application. \$\endgroup\$ Feb 22, 2019 at 22:14

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge that you have read and understand our privacy policy and code of conduct.

Not the answer you're looking for? Browse other questions tagged or ask your own question.