# How can I find the width and height of pixels on a camera display?

I am trying to determine the width and height of the LCD on the camera. I will use the Canon EOS-1DX Mark II as an example.

The display is written as 1,620,000 pixels. This is not intuitive to me as I would like the width and height. I have tried computing in the following way, using the advice of Why does viewfinder spec state 3 times more dots than there are pixels?

I assumed that there are 1,620,000/3=540,000 real pixels and the width:height is in 3:2 ratio (same as the sensor?). By simple arithmetic I arrived at a resolution of 900x600.

Additional Example: The 7D Mark II resolution is listed as 1,036,800 pixels. Using the same basic calculation I arrive at 720x480.

For both examples I arrive and nice round numbers.

Two questions:

1. Are my assumptions correct?

2. Why do manufacturers use this notation for lcd resolution?

• What photographic problem are you trying to solve? That is, how does this affect how a photo you wish to create will turn out? Aug 21, 2018 at 17:36

This is basic algebra. Assuming that you are correct that the LCD has a 3:2 aspect ratio (this is often true of the sensors in DSLRs, but not necessarily the LCDs - check the specs in your user manual for more info), then you have that `3x * 2x = 6x^2 = 1620000`, or `x = sqrt(1620000)/6`. This means `x` is about 517, from which you would then get the dimensions - `3x = 1559` and `2x = 1039`, so the resolution of the LCD is about 1559x1039.