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I'm looking for the lightest Mirrorless around (for a skydiving helmet). It must have a wired remote since it is inaccessible in freefall. According to Wikipedia, the original 2012 EOS M model is the lightest of all Canons, with which I can then use my existing EF lenses. However, it seems like it only uses a wifi remote.

My questions:

  1. Can any EOS-M camera use a wired remote? I'll use a blow switch eventually.
  2. Can any EOS-M camera use a programmed wireless remote? as in to program it to take a single photo every second or a burst in timed intervals.
  3. Can any other mirrorless on the market have a wired remote while weighing under 300g?

for reference: enter image description here

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  • \$\begingroup\$ You know Canon has an email. You can send like emails with questions to them. \$\endgroup\$
    – Andreas
    Commented Aug 16, 2018 at 12:30
  • \$\begingroup\$ 1. Their answer was no. I'll have to rely on aftermarket solutions and maybe even Magic Lantern 2. My third question did not involve Canons \$\endgroup\$
    – PIXP
    Commented Aug 16, 2018 at 12:38
  • \$\begingroup\$ Absolute curiosity here: why the 300g limit? \$\endgroup\$
    – OnBreak.
    Commented Aug 16, 2018 at 17:09
  • \$\begingroup\$ Why is WiFi not usable? You can establish a direct connection between any Android/iOS phone and the WiFi enabled EOS M models. This could be done before exiting the plane. You wouldn't need physical access to the camera at that point. \$\endgroup\$
    – Michael C
    Commented Aug 16, 2018 at 17:15
  • \$\begingroup\$ No 300g limit. I just used it as a reference figure because the older EOS M camera were light like this so i was asking if another comparable camera exists. \$\endgroup\$
    – PIXP
    Commented Aug 16, 2018 at 22:12

1 Answer 1

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For the EOS M, you can try the Audio Remote Shot Option via your smartphone. ( Smartphone must have a standard headphone Jack).

You will need to install the Tragic Lantern Firmware on your Camera.

From the Tragic Lantern Camera Menu, turn on the Audio Remote Shot option.

Download and install the Triggertrap App on your Smartphone.

You will also need to purchase the Triggertrap mobile dongle for Canon (about $10)

And an Audio to Audio Cable where one end goes into the Dongle and the other end into the Smartphone.

From the Triggertrap App, you should now be able to trigger the shutter and also use it for timelapse.

Someone introduced me to this a few years ago and although a little fiddly at first, it worked just fine.

And if this option is still available, then I can't see why it wont still work.

Good Luck

enter image description here

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  • \$\begingroup\$ This is getting closer to what I want. It won't be triggered by a loud noise right? Also can it be a button instead of a smart phone? If it's the headphones jack it is probably simple enough to have a clicker type switch attached on wire to the the triggertrap dongle \$\endgroup\$
    – PIXP
    Commented Aug 16, 2018 at 13:13
  • \$\begingroup\$ Also what's the difference between Magic and Tragic? \$\endgroup\$
    – PIXP
    Commented Aug 16, 2018 at 13:14
  • \$\begingroup\$ from what I recall, there was no loud noise. a simple red button on the smartphone screen that you touch and the shutter clicks with no additional noise. Regarding a clicker type button, I am not sure that this will work as this is an App based solution which activates the electronics in the dongle. Which in turn must produce a noise signal that goes through the mic input and triggers the shutter. \$\endgroup\$
    – Abdul N Quraishi
    Commented Aug 16, 2018 at 13:30
  • \$\begingroup\$ I think that solution could be hacked in to a biteswitch. The phone probably triggers a pulse from the audio jack and all you need to do is find out what the voltage is. Then use the biteswitch together with a battery of the same voltage will probably trigger the camera \$\endgroup\$
    – Andreas
    Commented Aug 16, 2018 at 16:01
  • \$\begingroup\$ It may be more complex than simple voltage. It may be pulsed signalling using the audio jack. \$\endgroup\$
    – Michael C
    Commented Aug 16, 2018 at 16:44

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