Timeline for How is the number of stops of benefit provided by VR determined?
Current License: CC BY-SA 3.0
9 events
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| Apr 13, 2017 at 12:43 | history | edited | CommunityBot |
replaced http://photo.stackexchange.com/ with https://photo.stackexchange.com/
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| Oct 4, 2014 at 3:25 | comment | added | Hugo | @MichaelClark Good that we cleared that then. And yes the concept stilll stands and I completely agree with you about the stop not being a linear unit, but rather exponential.:) | |
| Oct 4, 2014 at 0:54 | comment | added | Michael C | @Hugo Yeah,I totally didn't catch that. Still, the concept remains: two stops difference is not a linear unit of time, but rather a unit exponentially proportional to the beginning value. | |
| Oct 3, 2014 at 0:41 | comment | added | Hugo | @MichaelClark It is true that the difference between 1/125 second and 1/500 second is 1/167 second, but I have to clarify (for other readers) that when you refer to connersz "1/45 second" you're not saying that it actually is the difference between 1/60 second and 1/15 second (it is 1/20), but rather explaining what commersz though it represented. | |
| Oct 3, 2014 at 0:22 | comment | added | Michael C | @connersz The 1/45 second is simply the difference between 1/60 second and 1/15 second, but it is more accurate to say two stops, because the difference between 1/500 second and 1/125 second is also two stops (four times the amount of light strikes the sensor), even though the difference in time is only 1/166 second. The stop scale is logarithmic, not linear. | |
| Oct 2, 2014 at 10:35 | history | edited | Hugo | CC BY-SA 3.0 |
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| Oct 2, 2014 at 10:14 | comment | added | Hugo | @connersz First of by turning on the IS you dont gain an extra 1/45th of a second. It let's you increase the shutter speed by a factor of 4 (which is not the same thing mathematically). Regardless, it is usually not calculated but rather a matter of experience. Usually the IS of a modern camera let's you lower the shutter speed by a few stops (compared to IS turned off) before the shots get blurry again. This is not a hard limit since it depends on the resolution of the camera, the steadiness of the photographer etc. | |
| Oct 2, 2014 at 10:06 | comment | added | connersz | I know this is what it means but how can they calculate that extra 1/45th of a second like you mentioned? | |
| Oct 2, 2014 at 10:04 | history | answered | Hugo | CC BY-SA 3.0 |