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Dec 13 at 1:31 comment added scottbb @RomeoNinov the ratio of the image distance to the object distance is defined as the magnification: \$M = i/o\$. Of course, that depends on \$f\$ as well: \$M = (i-f)/f\$.
Dec 13 at 1:29 answer added scottbb timeline score: 1
Dec 10 at 4:42 vote accept Bram
Dec 9 at 22:41 comment added Michael C Sometimes the same words mean different things when used in different disciplines. How does photography (as opposed to physics) define "focal-plane"?
Dec 9 at 18:48 answer added Alan Marcus timeline score: 2
Dec 9 at 12:36 comment added Romeo Ninov @timvrhn, to be honest I was not sure about. But when I run the tool from OP it confirm my understanding. So I think this is a fact :)
Dec 9 at 12:30 comment added timvrhn @RomeoNinov I am not doubting you, you likely know way more about this than I do. It just does not seem like an opinion but rather a fact
Dec 9 at 10:56 comment added Romeo Ninov @timvrhn, and if you go to the link OP provide and check the focus you will see confirmation of my words.
Dec 9 at 10:53 comment added Romeo Ninov @timvrhn, do you know what mean the abbreviation IMHO? Also this is what my common sense tell me.
Dec 9 at 10:41 comment added timvrhn Is that an opinion or a fact @RomeoNinov?
Dec 9 at 10:29 comment added Romeo Ninov IMHO the ratio between object and image distances depends on the diopters of the lens
Dec 9 at 7:50 history asked Bram CC BY-SA 4.0